Most accurate length and barrel contour

[grayfox]

I've done a lot of those projections, basically look at it as a rt triangle, where angle x is very very small.
for very small angles, sin x = x.
sin x=opp (the deflection)/hypotenuse (L).

So vertical deflection =L*sin x, or L*x at 24" (I have a 24" barrel).

But we already know the "sides" of the barrel-triangle... the vertical is 0.0012" for a 24" (rounded up) barrel.

If I got this correct, so 24" barrel, deflection of 0.0012" (rounding up for a 24" barrel) for his 5 lb 4 oz barrel and 1 lb weight deflection, (all of which does not reflect, I think, the actual barrel condition at the shot, but anyway...)

Or, 0.0006"/ft travel. Total displacement across 100 yds, or 300 ft, would be proportional.

Deflection (1-way) at 300 ft = 0.0006*300 = 0.18".
For the 2-way deflection it would be 2x, or 0.36", and I would assume ctc.

Of course, we don't know if our real barrel has a 1-lb "weight" for the deflection/torque, and we don't have his exact barrel dimensions on our rifle, so ours might behave differently.